document.write( "Question 825686: The width, w, of a rectangle is 3/4 its length,l,.The width,w, of the rectangle is 12 inches.\r
\n" ); document.write( "\n" ); document.write( "What Is the perimeter and area in square ?
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Algebra.Com's Answer #497594 by sarcasticpie(12)\"\" \"About 
You can put this solution on YOUR website!
Hello :)\r
\n" ); document.write( "\n" ); document.write( "As you said, the width is \"%283%29%2F%284%29\" of the length. This would lead us to believe that the length is 4 parts, and 3 parts of it is 12 inches.\r
\n" ); document.write( "\n" ); document.write( "This can be written as \"%2812%29%2F%28l%29\" = \"%283%29%2F%284%29\" . Using cross multiplication, we'll get \"%283l%29%2F%283%29\" = \"%2812%2A4%29%2F%283%29\" , which ends up as 16 inches. Now we know that the length is 16 inches and the width is 12 inches.\r
\n" ); document.write( "\n" ); document.write( "a) Using our info, the perimeter is equal to 2(l+w)
\n" ); document.write( "= 2(16 + 12) inches
\n" ); document.write( "= 2(28) inches
\n" ); document.write( "= 56 inches\r
\n" ); document.write( "\n" ); document.write( "b) Area is equal to l times w
\n" ); document.write( "= 16 times 12
\n" ); document.write( "= 192 square inches\r
\n" ); document.write( "\n" ); document.write( "There you go! I hope it helps :) x
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