document.write( "Question 825764: A sailor in a sea starts sailing from a point A and goes 9km due north and then 32 km due east and then 15 km due north and stop. how much shortest distance from the starting point to the last? \n" ); document.write( "
Algebra.Com's Answer #497579 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Up is due north, right is due east. The black\r\n" );
document.write( "lines show his path from point A to point B.\r\n" );
document.write( "The green line AB shows the shortest distance\r\n" );
document.write( "from point A to point B.\r\n" );
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document.write( "Draw in the following red lines:\r\n" );
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document.write( "The shortest distance, AB, is the hypotenuse of right triangle ABC.\r\n" );
document.write( "By the Pythagorean theorem,\r\n" );
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document.write( "ABē = ACē + CBē, and CB = 9km + 15km = 24km\r\n" );
document.write( "ABē = 32ē + 24ē\r\n" );
document.write( "ABē = 1024 + 576\r\n" );
document.write( "ABē = 1600\r\n" );
document.write( " AB = √1600  \r\n" );
document.write( " AB = 40km\r\n" );
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document.write( "Edwin
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