Algebra.Com's Answer #497571 by Edwin McCravy(20055)  You can put this solution on YOUR website! If is in Q2, then is equal to: \n" );
document.write( "a) -√3/2 \n" );
document.write( "b) √3/2 \n" );
document.write( "c) 3/4 \n" );
document.write( "d) -3/4 \n" );
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document.write( "It's none of those answers. I'll do it two ways to show that the\r\n" );
document.write( "correct answer is , as the other tutor has just flatly \r\n" );
document.write( "stated with no explanation. (BTW, a tutor should do more than give\r\n" );
document.write( "answers. Too many teachers know their subject but can't teach it!).\r\n" );
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document.write( "First way:\r\n" );
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document.write( "Draw the picture of angle in the second quadrant Q2. \r\n" );
document.write( "Since the cosecant is hypotenuse/opposite or r/y, and since we are given \r\n" );
document.write( " , make r=2 and y= , and calculate x using the \r\n" );
document.write( "Pythagorean theorem:\r\n" );
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document.write( " x²+y² = r²\r\n" );
document.write( "x²+ = 2²\r\n" );
document.write( " x²+3 = 4\r\n" );
document.write( " x² = 1\r\n" );
document.write( " x = ±√1\r\n" );
document.write( " x = ±1, we take x = -1 \r\n" );
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document.write( "We take x negative because it goes left from the origin, \r\n" );
document.write( "and we ALWAYS take r positive because it begins on the\r\n" );
document.write( "right side of the x-axis and doesn't change its sign when\r\n" );
document.write( "it swings around into the other quadrants. \r\n" );
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document.write( "We want . The cosine is adjacent/hypotenuse or x/r,\r\n" );
document.write( "so       \r\n" );
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document.write( "Second way, using these identities:\r\n" );
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document.write( "1. \r\n" );
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document.write( "2.   \r\n" );
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document.write( "Using 1.,\r\n" );
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document.write( "Cross-multiply:\r\n" );
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document.write( "Using 2.,\r\n" );
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document.write( "Since the cosine is negative in the second quadrant Q2,\r\n" );
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document.write( "Edwin \n" );
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