document.write( "Question 825765: If csc theta = 2/√3, P theta is in 2 Q, then cos theta is equal to:\r
\n" ); document.write( "\n" ); document.write( "a) -√3/2
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Algebra.Com's Answer #497571 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
If \"csc%28theta%29+=+2%2Fsqrt%283%29%2C+%7B%7B%7BP%28theta%29\" is in Q2, then \"cos%28theta%29\" is equal to:
\n" ); document.write( "a) -√3/2
\n" ); document.write( "b) √3/2
\n" ); document.write( "c) 3/4
\n" ); document.write( "d) -3/4
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document.write( "It's none of those answers.  I'll do it two ways to show that the\r\n" );
document.write( "correct answer is \"-1%2F2\", as the other tutor has just flatly \r\n" );
document.write( "stated with no explanation.  (BTW, a tutor should do more than give\r\n" );
document.write( "answers. Too many teachers know their subject but can't teach it!).\r\n" );
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document.write( "First way:\r\n" );
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document.write( "Draw the picture of angle \"theta\" in the second quadrant Q2. \r\n" );
document.write( "Since the cosecant is hypotenuse/opposite or r/y, and since we are given \r\n" );
document.write( "\"csc%28theta%29=2%2Fsqrt%283%29\", make r=2 and y=\"sqrt%283%29\", and calculate x using the \r\n" );
document.write( "Pythagorean theorem:\r\n" );
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document.write( "    x²+y² = r²\r\n" );
document.write( "x²+\"%28sqrt%283%29%29%5E2\" = 2²\r\n" );
document.write( "    x²+3 = 4\r\n" );
document.write( "      x² = 1\r\n" );
document.write( "       x = ±√1\r\n" );
document.write( "       x = ±1, we take x = -1 \r\n" );
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document.write( "We take x negative because it goes left from the origin, \r\n" );
document.write( "and we ALWAYS take r positive because it begins on the\r\n" );
document.write( "right side of the x-axis and doesn't change its sign when\r\n" );
document.write( "it swings around into the other quadrants. \r\n" );
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document.write( "We want \"cos%28theta%29\".  The cosine is adjacent/hypotenuse or x/r,\r\n" );
document.write( "so \"cos%28theta%29\"\"%22%22=%22%22\"\"x%2Fr\"\"%22%22=%22%22\"\"%28-1%29%2F2\"\"%22%22=%22%22\"\"-1%2F2\"\r\n" );
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document.write( "--------------------------------\r\n" );
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document.write( "Second way, using these identities:\r\n" );
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document.write( "1.  \"csc%28theta%29=1%2Fsin%28theta%29\"\r\n" );
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document.write( "2.  \"sin%5E2%28theta%29%2Bcos%5E2%28theta%29\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "Using 1.,\r\n" );
document.write( "   \r\n" );
document.write( "     \"csc%28theta%29\"\"%22%22=%22%22\"\"1%2Fsin%28theta%29\"\r\n" );
document.write( "     \"2%2Fsqrt%283%29\"\"%22%22=%22%22\"\"1%2Fsin%28theta%29\"\r\n" );
document.write( "Cross-multiply:\r\n" );
document.write( "     \"2sin%28theta%29\"\"%22%22=%22%22\"\"sqrt%283%29\"\r\n" );
document.write( "      \"sin%28theta%29\"\"%22%22=%22%22\"\"sqrt%283%29%2F2\"\r\n" );
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document.write( "Using 2.,\r\n" );
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document.write( "    \"sin%5E2%28theta%29%2Bcos%5E2%28theta%29\"\"%22%22=%22%22\"\"1\"\r\n" );
document.write( "     \"%28sqrt%283%29%2F2%29%5E2%2Bcos%5E2%28theta%29\"\"%22%22=%22%22\"\"1\"\r\n" );
document.write( "         \"3%2F4%2Bcos%5E2%28theta%29\"\"%22%22=%22%22\"\"1\"\r\n" );
document.write( "            \"cos%5E2%28theta%29\"\"%22%22=%22%22\"\"1-3%2F4\"\r\n" );
document.write( "            \"cos%5E2%28theta%29\"\"%22%22=%22%22\"\"4%2F4-3%2F4\"\r\n" );
document.write( "            \"cos%5E2%28theta%29\"\"%22%22=%22%22\"\"1%2F4\"\r\n" );
document.write( "              \"cos%28theta%29\"\"%22%22=%22%22\"\"%22%22+%2B-+sqrt%281%2F4%29\" \r\n" );
document.write( "              \"cos%28theta%29\"\"%22%22=%22%22\"\"%22%22+%2B-+1%2F2\"\r\n" );
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document.write( "Since the cosine is negative in the second quadrant Q2,\r\n" );
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document.write( "              \"cos%28theta%29\"\"%22%22=%22%22\"\"-1%2F2\"\r\n" );
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document.write( "Edwin
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