document.write( "Question 825715: If sinθ= 4/5 and θ terminates in Quadrant II, find the exact value of sin2θ.
\n" ); document.write( "F. -24/25
\n" ); document.write( "G. 8/5 (I chose this one and it was wrong)
\n" ); document.write( "H.-12/25
\n" ); document.write( "J. 24/25
\n" ); document.write( "Sorry I found the typo I submitted in one of my previous questions. So sorry about that. \n" ); document.write( "

Algebra.Com's Answer #497552 by MathTherapy(10555) $\"\"$ $\"About$

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If sinθ= 4/5 and θ terminates in Quadrant II, find the exact value of sin2θ.
\n" ); document.write( "F. -24/25
\n" ); document.write( "G. 8/5 (I chose this one and it was wrong)
\n" ); document.write( "H.-12/25
\n" ); document.write( "J. 24/25
\n" ); document.write( "Sorry I found the typo I submitted in one of my previous questions. So sorry about that.\r
\n" ); document.write( "\n" ); document.write( "


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document.write( "sin θ =  = 
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document.write( "Since the opposite side (O) is 4 and the hypotenuse (H)is 5, the adjacent side (A) MUST = 3,
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document.write( "as this represents a 3-4-5 special triangle\r
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document.write( "Since θ terminates in the 2nd quadrant, where cos is < 0 (negative), we get:
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document.write( "cos θ =  \r
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document.write( "sin 2 θ = 2 sin θ cos θ (double-angle identity)
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document.write( "Therefore, sin 2 θ = ________ (CHOICE H) \n" );
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