document.write( "Question 825744: A home’s backyard is 20 feet by 15 feet. What are its perimeter and area? \n" ); document.write( "
Algebra.Com's Answer #497550 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Area \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "A = L*W\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "A = 20*15\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "A = 300 square feet\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=======================================================\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Perimeter\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "P = 2(L + W)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "P = 2*(20+15)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "P = 2*35\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "P = 70 feet\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );