document.write( "Question 825685: MATH PROBLEM: SUE TRAVELS AT A RATE OF 42 MPH. BOB TRAVELS AT A RATE OF 58 MPH AND REACHES HIS DESTINATION 4 HOURS EARLIER THAN SUE. HOW LONG DOES IT TAKE EACH PERSON TO REACH THEIR DESTINATIONS? HOW FAR IS THE TRIP TO THEIR GRANDPARENTS HOUSE? \n" ); document.write( "
Algebra.Com's Answer #497540 by mananth(16946)\"\" \"About 
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let the distance be x\r
\n" ); document.write( "\n" ); document.write( "time taken by Sue = x/42\r
\n" ); document.write( "\n" ); document.write( "time taken by Bob = x/58\r
\n" ); document.write( "\n" ); document.write( "time Sue = Time Bob + 4 hours\r
\n" ); document.write( "\n" ); document.write( "x/42= x/58 +4\r
\n" ); document.write( "\n" ); document.write( "x/42-x/58 = 4\r
\n" ); document.write( "\n" ); document.write( "58x-42x= 4*58*42\r
\n" ); document.write( "\n" ); document.write( "16x= 4*58*42\r
\n" ); document.write( "\n" ); document.write( "x=4*58*42/16\r
\n" ); document.write( "\n" ); document.write( "x=29*21\r
\n" ); document.write( "\n" ); document.write( "x= 609 miles distance to grandpa's house\r
\n" ); document.write( "\n" ); document.write( "You can calculate time by the formula t= d/r for each of them
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