document.write( "Question 825698: If secθ= 4/5 and θ terminates in Quadrant II, find the exact value of sin2θ.
\n" ); document.write( "F. -24/25
\n" ); document.write( "G. 8/5 (I chose this one and it was wrong)
\n" ); document.write( "H.-12/25
\n" ); document.write( "J. 24/25 \n" ); document.write( "
Algebra.Com's Answer #497516 by Seutip(231)\"\" \"About 
You can put this solution on YOUR website!
If secθ= 4/5 and θ terminates in Quadrant II, find the exact value of sin2θ.\r
\n" ); document.write( "\n" ); document.write( "cos^2θ + sin^2θ = 1 because of Pythagorean identities\r
\n" ); document.write( "\n" ); document.write( "Therefore sin^2θ = 1- cos^2θ\r
\n" ); document.write( "\n" ); document.write( "cosθ = 1/secθ\r
\n" ); document.write( "\n" ); document.write( "So,\r
\n" ); document.write( "\n" ); document.write( "sin^2θ = 1- cos^2θ
\n" ); document.write( "sin^2θ = 1- (1/secθ)^2\r
\n" ); document.write( "\n" ); document.write( "sin^2θ = 1- {1/ (4/5)}^2
\n" ); document.write( "sin^2θ = 1- (5/4)^2
\n" ); document.write( "sin^2θ = 1- (25/16)
\n" ); document.write( "sin^2θ = 1- (25/16)
\n" ); document.write( "sin^2θ = 16/16 - (25/16)
\n" ); document.write( "sin^2θ = 16-25 /16
\n" ); document.write( "sin^2θ = -9/16\r
\n" ); document.write( "\n" ); document.write( "Tht's the answer :)
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