document.write( "Question 825694: 8. Radioactive materials like uranium follow the law of uninhibited decay, which is an Exponential Model. This decay causes radiation. All radioactive substances have a specific half-life, which is the time required for half of the radioactive substance to decay. Uninhibited Radioactive Decay is given by the formula:\r
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\n" ); document.write( "The half-life of thorium-229 is 7,340 years. How long will it take for a sample of this substance to decay to 20% of its original amount?
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Algebra.Com's Answer #497515 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
The exponential decay model is based on \"A=I%2Ae%5E%28kt%29\"; some people might prefer a \"-k\", but however the choice, consistency is needed.\r
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\n" ); document.write( "\n" ); document.write( "A = amount at time t
\n" ); document.write( "I = initial amount, for t=0
\n" ); document.write( "k = a constant
\n" ); document.write( "t = time in years\r
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\n" ); document.write( "\n" ); document.write( "First, find k.
\n" ); document.write( "\"A%2FI=e%5E%28kt%29\"
\n" ); document.write( "\"ln%28A%2FI%29=ln%28e%5E%28kt%29%29\"
\n" ); document.write( "\"ln%28A%2FI%29=kt%2A1\"
\n" ); document.write( "\"k=%281%2Ft%29ln%28A%2FI%29\"
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\n" ); document.write( "The given halflife is for t=7340 years, and for which \"A=%281%2F2%29I\";
\n" ); document.write( "\"k=%281%2F7340%29ln%281%2F2%29\"
\n" ); document.write( "\"k=-9.44%2A10%5E%28-5%29\"
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\n" ); document.write( "Not sure if this will render properly but the model is:
\n" ); document.write( "\"highlight%28A=I%2Ae%5E%28-0.0000944%2At%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Your specific question will use A=0.20, and I=1. You would then solve the model equation for t.
\n" ); document.write( "Recall from, \"First, find k\", a slight change in step gives: \"highlight%28t=%281%2Fk%29ln%28A%2FI%29%29\"; just substitute the values known.
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