document.write( "Question 825698: If secθ= 4/5 and θ terminates in Quadrant II, find the exact value of sin2θ.
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document.write( "F. -24/25
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document.write( "G. 8/5 (I chose this one and it was wrong)
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document.write( "H.-12/25
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document.write( "J. 24/25 \n" );
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Algebra.Com's Answer #497514 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! I'm going to use x in place of θ (it's easier to type)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sec(x) = 4/5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1/cos(x) = 4/5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cos(x) = 5/4 ... take the reciprocal of both sides\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cos^2(x) = 25/16 ... square both sides\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin^2(x) + cos^2(x) = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin^2(x) + 25/16 = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin^2(x) = 1 - 25/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin^2(x) = 16/16 - 25/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin^2(x) = (16 - 25)/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin^2(x) = -9/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin(x) = sqrt(-9/16)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As you can see in the last step above, we have sqrt(-9/16), but we cannot take the square root of a negative number and get a real number as a result. So this leads me to think that there's a typo somewhere. Please double check. Thanks. \n" ); document.write( " |