document.write( "Question 69815: heres my problem its probly so easy but i cant understand it.\r
\n" ); document.write( "\n" ); document.write( "4/5t - 1 = 1/5t + 5
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Algebra.Com's Answer #49751 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
\"4%2F5t+-+1+=+1%2F5t+%2B+5\" First, we'll ge rid of the fractions by multiplying each term in the equation by 5t --- the LCM\r
\n" ); document.write( "\n" ); document.write( "\"4%285t%2F5t%29-1%285t%29=1%285t%2F5t%29%2B5%285t%29\" this gives us\r
\n" ); document.write( "\n" ); document.write( "\"4-5t=1%2B25t\" subtract 1 from and add 5t to both sides of the equation\r
\n" ); document.write( "\n" ); document.write( "\"4-5t%2B5t-1=1-1%2B25t%2B5t\" collect like terms\r
\n" ); document.write( "\n" ); document.write( "\"3=30t\" divide both sides by 30\r
\n" ); document.write( "\n" ); document.write( "\"t=3%2F30=%281%2F10%29+or+0.1\"\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "\"4%2F%285%2A.1%29-1=1%2F%285%2A.1%29%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"4%2F.5-1=1%2F.5%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"8-1=2%2B5\"
\n" ); document.write( "\"7=7\"\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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