document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=825631>Question 825631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this question\r<BR>\n" );
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document.write( "The measure of angle r is 12 degrees more than three times the measure of angle s.If angle s and angle r are supplementary angles find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #497501 by </B><A HREF=/tutors/aboutme.mpl?userid=Seutip><B>Seutip(231)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Seutip><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Seutip><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=497501\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let<BR>\n" );
document.write( "     x - be angle s<BR>\n" );
document.write( "     x+12 - be angle r\r<BR>\n" );
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document.write( "If r and s re supplementary, therefore r+s=180 right?\r<BR>\n" );
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document.write( "x+ (x+12) = 180<BR>\n" );
document.write( "2x = 168<BR>\n" );
document.write( "x = 84\r<BR>\n" );
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document.write( "Therefore \r<BR>\n" );
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document.write( "s = 84 degrees<BR>\n" );
document.write( "r = 96 degrees </SPAN>\n" );
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