document.write( "Question 825676: How do you substitute .05m+20+20=.10(m-100)+15+20
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Algebra.Com's Answer #497489 by stanbon(75887)\"\" \"About 
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0.05m+20+20 = 0.10(m-100)+15+20
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\n" ); document.write( "0.05m + 40 = 0.10m-10 + 35
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\n" ); document.write( "0.05m + 40 = 0.10m+25
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\n" ); document.write( "0.05m = 15
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\n" ); document.write( "m = 1500/5
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\n" ); document.write( "m = 300
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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