document.write( "Question 825676: How do you substitute .05m+20+20=.10(m-100)+15+20
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #497489 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 0.05m+20+20 = 0.10(m-100)+15+20 \n" ); document.write( "-------- \n" ); document.write( "0.05m + 40 = 0.10m-10 + 35 \n" ); document.write( "----- \n" ); document.write( "0.05m + 40 = 0.10m+25 \n" ); document.write( "------ \n" ); document.write( "0.05m = 15 \n" ); document.write( "---- \n" ); document.write( "m = 1500/5 \n" ); document.write( "---- \n" ); document.write( "m = 300 \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |