document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69832>Question 69832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle increased by 5 is equal to 40 decreased by 4 times the area.  Let a stand for the area. Solve for a. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49748 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49748\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a=area of rectangle<BR>\n" );
document.write( "Then a+5=area increased by 5<BR>\n" );
document.write( "4a= 4 times the area\r<BR>\n" );
document.write( "\n" );
document.write( "Now we are told that:\r<BR>\n" );
document.write( "\n" );
document.write( "a+5=40-4a  add 4a to and subtract 5 from both sides\r<BR>\n" );
document.write( "\n" );
document.write( "a+4a+5-5=40-5-4a+4a  collect like terms\r<BR>\n" );
document.write( "\n" );
document.write( "5a=35  divide both sides by 5\r<BR>\n" );
document.write( "\n" );
document.write( "a=7 sq units------------------------area of rectangle\r<BR>\n" );
document.write( "\n" );
document.write( "CK\r<BR>\n" );
document.write( "\n" );
document.write( "7+5=40-4*7<BR>\n" );
document.write( "12=40-28<BR>\n" );
document.write( "12=12\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps----ptaylor<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );