document.write( "Question 825568: The bottom of a box is to be a rectangle with a perimeter of 42cm. The box must have a height of 10c. what is dimensions of the box give you the maximum volume? What is the maximum volume?\r
\n" ); document.write( "\n" ); document.write( "*Please show all your work so that I can see how you got your answer, Thanks!!!
\n" ); document.write( "

Algebra.Com's Answer #497402 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
bottom, w by y.
\n" ); document.write( "\"2w%2B2y=42\";\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "volume is \"v=wy%2A10\";\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "From perimeter equation,
\n" ); document.write( "w+y=21
\n" ); document.write( "w=21-y;
\n" ); document.write( "Substitute...
\n" ); document.write( "v=(21-y)y*10
\n" ); document.write( "\"v=210y-10y%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Not finished, short on time here; but quadratic equation in terms of y, so you can find the maximum...
\n" ); document.write( "coefficient on y^2 is a negative constant, so v has a maximum.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You can take average of the roots (for when v=0) and that is the y length so you can then use it to find w. If this a Calculus problem? You could find derivative and equate to zero to find y...
\n" ); document.write( "
\n" ); document.write( "
\n" );