document.write( "Question 825369: The first and last term of a geometric series are 2 and 2048 respectively. The sum of the series is 273. Find the common ratio and the number of terms.
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Algebra.Com's Answer #497354 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
This problem is not possible.

\n" ); document.write( "Here's why. The formula for the nth term of a geometric sequence is:
\n" ); document.write( "\"a%5Bn%5D+=+a%5B1%5D%2Ar%5E%28%28n-1%29%29\"
\n" ); document.write( "with \"a%5B1%5D\" being the first term, \"r\" being the common ratio, and \"n\" being the number of the term. So 2 and 2048 should fit this formula:
\n" ); document.write( "\"2048+=+2%2Ar%5E%28%28n-1%29%29\"
\n" ); document.write( "If we realize that 2048 = 2*2*2*2*2*2*2*2*2*2*2 then we know that the only factors of 2048 are 2's or powers of 2. 2's and powers of 2 cannot add up to an odd number like 273.

\n" ); document.write( "If we don't know this about 2048 we could try to go further. Dividing both sides by 2 we get:
\n" ); document.write( "\"1024+=+r%5E%28%28n-1%29%29\"
\n" ); document.write( "Next we will use the formula for the sum of a geometric series:
\n" ); document.write( "\"S%5Bn%5D+=+a%5B1%5D%28%281-r%5En%29%2F%281-r%29%29\"
\n" ); document.write( "where \"S%5Bn%5D\" is the sum of the first n terms, \"a%5B1%5D\" is the first term, \"r\" is the common ratio, and \"n\" is the number of terms. Substituting in our values for the sum and the first term we get:
\n" ); document.write( "\"273+=+2%28%281-r%5En%29%2F%281-r%29%29\"
\n" ); document.write( "Multiplying each side by (1-r) [to eliminate the fraction] we get:
\n" ); document.write( "\"273%281-r%29+=+2%281-r%5En%29\"
\n" ); document.write( "which simplifies to:
\n" ); document.write( "\"273-273r+=+2%281-r%5En%29\"
\n" ); document.write( "Next we return to our earlier equation:
\n" ); document.write( "\"1024+=+r%5E%28%28n-1%29%29\"
\n" ); document.write( "If we multiply each side of this by r we get:
\n" ); document.write( "\"1024%2Ar+=+r%5E%28%28n-1%29%29+%2Ar\"
\n" ); document.write( "On the right side we use the rule for exponents when multiplying (i.e. add the exponents:
\n" ); document.write( "\"1024%2Ar+=+r%5E%28%28n-1%29%29+%2Ar%5E1\"
\n" ); document.write( "\"1024r+=+r%5E%28%28n-1%29%2B1%29\"
\n" ); document.write( "\"1024r+=+r%5En\"
\n" ); document.write( "This gives us an expression to use back in:
\n" ); document.write( "\"273-273r+=+2%281-r%5En%29\"
\n" ); document.write( "Substituting in 1024r:
\n" ); document.write( "\"273-273r+=+2%281-1024r%29\"
\n" ); document.write( "Now we can solve for r. Multiplying out the right side:
\n" ); document.write( "\"273-273r+=+2-2048r\"
\n" ); document.write( "Adding 2048r:
\n" ); document.write( "\"273%2B1775r+=+2\"
\n" ); document.write( "Subtracting 273:
\n" ); document.write( "\"1775r+=+-271\"
\n" ); document.write( "Dividing by 1775:
\n" ); document.write( "\"r+=+%28-271%29%2F1775\"
\n" ); document.write( "With this value for \"r\", it will be impossible for the series to start at 2 and eventually get to 2048. (Try it and see!).

\n" ); document.write( "Since the formulas for geometric series do not work with a first term of 2, a last term of 2048 and a sum of 273, these numbers cannot reflect a geometric series.
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