document.write( "Question 823038: How many liters of 40% acid solution must be mixed with 10 liters of a 65% acid solution to get a 45% acid solution? \n" ); document.write( "
Algebra.Com's Answer #497328 by josgarithmetic(39617)\"\" \"About 
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Assign Variables:
\n" ); document.write( "v = How many liters of 40% acid
\n" ); document.write( "L = 40%, the low concentration of acid
\n" ); document.write( "R = 10 liters of 65%, higher concentrated acid
\n" ); document.write( "H = 65% the higher concentration acid
\n" ); document.write( "T = 45%, the target concentration of acid wanted\r
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\n" ); document.write( "\n" ); document.write( "{pure amount of acid}/{amount of blend}={resulting concentration}\r
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\n" ); document.write( "\n" ); document.write( "\"Pure+Acid+=+L%2Av%2BH%2AR\", which is 100 times larger because direct percents are used;\r
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\n" ); document.write( "\n" ); document.write( "\"Amount+of+Blend+=+v%2BR\"\r
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\n" ); document.write( "\n" ); document.write( "Equation to solve:
\n" ); document.write( "'
\n" ); document.write( "\"%28Lv%2BHR%29%2F%28v%2BR%29=T\"
\n" ); document.write( "Solve for the UNKNOWN variable, v.
\n" ); document.write( "Replace all other variables with their given values and compute v.
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