document.write( "Question 825454: How would you put x^2+7x=2x^2+6 in standard form \n" ); document.write( "

Algebra.Com's Answer #497307 by josgarithmetic(39625) $\"\"$ $\"About$

You can put this solution on YOUR website!
This is a question about Completing The Square.
\n" ); document.write( "Simplify what you first can, and then complete the square, simplify more, and put into form of $\"%28x-h%29%5E2%2Bk=0\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2B7x-x%5E2=2x%5E2%2B6-x%5E2\"$
\n" ); document.write( " $\"7x=%282-1%29x%5E2%2B6\"$
\n" ); document.write( " $\"7x=x%5E2%2B6\"$
\n" ); document.write( " $\"0=x%5E2%2B6-7x\"$
\n" ); document.write( " $\"x%5E2-7x%2B6=0\"$ , general form.\r
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\n" ); document.write( "\n" ); document.write( "The part, $\"x%5E2-7x\"$ , represents the area of a rectangle, x(x-7). You could draw this and figure which region beyond the square portion to cut in half and arrange along another edge, and form an expression for the missing square corner...\r
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\n" ); document.write( "\n" ); document.write( "The square term to add and subtract is $\"%28-7%2F2%29%5E2=49%2F4\"$ ;
\n" ); document.write( " $\"x%5E2-7x%2B6%2B49%2F4-49%2F4=0\"$
\n" ); document.write( " $\"x%5E2-7x%2B49%2F4%2B6-49%2F4=0\"$
\n" ); document.write( " $\"%28x%5E2-7x%2B49%2F4%29%2B6-49%2F4=0\"$
\n" ); document.write( " $\"%28x-7%2F2%29%5E2%2B6%2A4%2F4-49%2F4=0\"$
\n" ); document.write( " $\"%28x-7%2F2%29%5E2%2B%2824-49%29%2F4=0\"$
\n" ); document.write( " $\"highlight%28%28x-7%2F2%29%5E2-25%2F4=0%29\"$ , DONE. \n" ); document.write( "

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