document.write( "Question 825317: Two vertices of a right triangle are (0,1) and (0,6). The area of the triangle is 10 square units. Which point could be the third vertex of the triangle? \n" ); document.write( "
Algebra.Com's Answer #497219 by josgarithmetic(39618)\"\" \"About 
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This has four different possible solutions. Try using (0,1) and (0,6) to be the segment of one of the legs. Another point may be (a, 6), for \"a%3E0\". Draw this so you see it.\r
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\n" ); document.write( "\n" ); document.write( "The lengths of the two legs are:\r
\n" ); document.write( "\n" ); document.write( "5, and a.\r
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\n" ); document.write( "\n" ); document.write( "The length of the hypotenuse is:\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28%286-1%29%5E2%2B%28a-0%29%5E2%29\"
\n" ); document.write( "\"sqrt%2825%2Ba%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Can we find a without using the hypotenuse?
\n" ); document.write( "Area formula gives \"%281%2F2%29a%2A5=10\";
\n" ); document.write( "\"a=%282%2F1%29%281%2F5%2910=4\".\r
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\n" ); document.write( "\n" ); document.write( "That one possible point is therefore, (4, 6).
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