document.write( "Question 825324: a man travels 200kms with a uniform speed of xkm per hour, the distance could have been covered in 2hours less had the speed been (x+5)km per hour.Calculate the value of x.
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Algebra.Com's Answer #497216 by ankor@dixie-net.com(22740)\"\" \"About 
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a man travels 200kms with a uniform speed of xkm per hour, the distance could have been covered in 2hours less had the speed been (x+5)km per hour.
\n" ); document.write( "Calculate the value of x.
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\n" ); document.write( "Write time equation; time = dist/speed
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\n" ); document.write( "\"200%2Fx\" - \"200%2F%28%28x%2B5%29%29\" = 2
\n" ); document.write( "multip0ly by x(x+5), cancel the denominators
\n" ); document.write( "200(x+5) - 200x = 2x(x+5)
\n" ); document.write( "200x + 1000 - 200x = 2x^2 + 10x
\n" ); document.write( "Combine on the right to form a quadratic equation
\n" ); document.write( "0 = 2x^2 + 10x - 1000
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "x^2 + 5x - 500 = 0
\n" ); document.write( "factors to
\n" ); document.write( "(x+25)(x-20) = 0
\n" ); document.write( "positive solution
\n" ); document.write( "x = 20
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\n" ); document.write( "Check this by finding the times
\n" ); document.write( "200/20 = 10 hrs
\n" ); document.write( "200/25 = 8 hrs
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