document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=825268>Question 825268</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I actually dont know if this is a geometry question but it has rectangles, perimeter, and area in it. (Sorry if I selected the topic wrong)\r<BR>\n" );
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document.write( "Here is my question:<BR>\n" );
document.write( "A rectangle has a perimeter of 40m and an area of 91m^2. If the length is longer than the width, find the length.\r<BR>\n" );
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document.write( "I dont know if my solution is right but i think it is absolutely wrong. Can you please correct me?\r<BR>\n" );
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document.write( "(This is what I understood about the problem)<BR>\n" );
document.write( "perimeter of a rectangle = 40m<BR>\n" );
document.write( "area of rectangle= 90m^2<BR>\n" );
document.write( "( Perimeter of a rectangle is 2l+2w right? while area is l*w)<BR>\n" );
document.write( "So I Put it this way<BR>\n" );
document.write( "2l+2w= 40m<BR>\n" );
document.write( "l*w= 90 m^2\r<BR>\n" );
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document.write( "That is what I tried I dont know what to do. Please help me on this one<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #497212 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=497212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "I actually dont know if this is a geometry question but it has rectangles, perimeter, and area in it. (Sorry if I selected the topic wrong)\r<BR>\n" );
document.write( "\n" );
document.write( "Here is my question:<BR>\n" );
document.write( "A rectangle has a perimeter of 40m and an area of 91m^2. If the length is longer than the width, find the length.\r<BR>\n" );
document.write( "\n" );
document.write( "I dont know if my solution is right but i think it is absolutely wrong. Can you please correct me?\r<BR>\n" );
document.write( "\n" );
document.write( "(This is what I understood about the problem)<BR>\n" );
document.write( "perimeter of a rectangle = 40m<BR>\n" );
document.write( "area of rectangle= 90m^2<BR>\n" );
document.write( "( Perimeter of a rectangle is 2l+2w right? while area is l*w)<BR>\n" );
document.write( "So I Put it this way<BR>\n" );
document.write( "2l+2w= 40m<BR>\n" );
document.write( "l*w= 90 m^2\r<BR>\n" );
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document.write( "That is what I tried I dont know what to do. Please help me on this one<BR>\n" );
document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\"><BR>\n" );
document.write( "You're correct up to that point, with the exception that the area is NOT <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90m%5E2 ALIGN=MIDDLE  ALT=\"90m%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, but <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=91m%5E2 ALIGN=MIDDLE  ALT=\"91m%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "I'll finish it for you!!<BR>\n" );
document.write( "2L + 2W = 40____2(L + W) = 2(20)_____L + W = 20<BR>\n" );
document.write( "L = 20 – W ----- eq (i)<BR>\n" );
document.write( "LW = 91 -------- eq (ii) <BR>\n" );
document.write( "W(20 – W) = 91 ------- Substituting 20 – W for L in eq (ii)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20W+-+W%5E2+=+91 ALIGN=MIDDLE  ALT=\"20W+-+W%5E2+=+91\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W%5E2+-+20W+%2B+91+=+0 ALIGN=MIDDLE  ALT=\"W%5E2+-+20W+%2B+91+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "(W - 7)(W - 13) = 0<BR>\n" );
document.write( "W – 7 = 0		   OR			W – 13 = 0<BR>\n" );
document.write( "W, or width = 7		   OR			W = 13\r<BR>\n" );
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document.write( "If W, or width = 7, then length = 13<BR>\n" );
document.write( "If W, or width = 13, then length = 7\r<BR>\n" );
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document.write( "Since the width's measurement is less than that of the length's, then width is: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%287%29 ALIGN=MIDDLE  ALT=\"highlight_green%287%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and length is: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2813%29 ALIGN=MIDDLE  ALT=\"highlight_green%2813%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "You can do the check!! \r<BR>\n" );
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document.write( "Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.<BR>\n" );
document.write( "Further help is available, online or in-person, for a fee, obviously. \r<BR>\n" );
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document.write( "For FREE info and answers to questions about the ASVAB exam, the NYS 3 – 8 city/state wide exams, <BR>\n" );
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