document.write( "Question 69774: Please someone help me! I need to rewrite this function in turning point form
\n" ); document.write( "y=x^+4x+3
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Algebra.Com's Answer #49721 by stanbon(75887)\"\" \"About 
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rewrite this function in turning point form
\n" ); document.write( "y=x^2+4x+3
\n" ); document.write( "The form is y-k=(x-h)^2 where (h,k) is the vertex or turning point.\r
\n" ); document.write( "\n" ); document.write( "Rewrite as:
\n" ); document.write( "y-3 = x^2+4x
\n" ); document.write( "Complete the square on the right side and keep the equation balanced:
\n" ); document.write( "y-3+? = x^2+4x+?
\n" ); document.write( "y--3+4 = x^2+4x+4
\n" ); document.write( "y+1 = (x+2)^2
\n" ); document.write( "Therefore:
\n" ); document.write( "The vertex or \"turning point\" is at x-2 , y=-1\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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