document.write( "Question 825269: My question is about ratio.\r
\n" ); document.write( "\n" ); document.write( "The ratio of two numbers is 3:5. If 4 are both added to both numbers the resulting ratio will be 7:11, find the smaller number.\r
\n" ); document.write( "\n" ); document.write( "I hope you can help me \n" ); document.write( "
Algebra.Com's Answer #497197 by rothauserc(4718)\"\" \"About 
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x/y = 3/5
\n" ); document.write( "5x = 3y
\n" ); document.write( "y = 5x/3
\n" ); document.write( "(x+4) / (y+4) = 7/11
\n" ); document.write( "11*(x+4) = 7 * (y+4)
\n" ); document.write( "11x +44 = 7y +28
\n" ); document.write( "11x = 7y -16
\n" ); document.write( "substitute for y in second ratio with value for y in first ratio
\n" ); document.write( "11x = 7*(5x/3) -16
\n" ); document.write( "11x = 35x/3 -16
\n" ); document.write( "multiply both sides of = by 3
\n" ); document.write( "33x = 35x -48
\n" ); document.write( "-2x = -48
\n" ); document.write( "x = 24
\n" ); document.write( "use first ratio to solve for y
\n" ); document.write( "y = (5*24) / 3 = 40
\n" ); document.write( "note that 24/40 = 3/5 and
\n" ); document.write( "28/44 = 7/11
\n" ); document.write( "the smallest number is x = 24\r
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