document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=825288>Question 825288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the direction of the final displacement of a car which travels 10 km south, 2 km west, and then 5 km east?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #497185 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=497185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the direction of the final displacement of a car which travels 10 km south, 2 km west, and then 5 km east?<BR>\n" );
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document.write( "Start: (0,0)<BR>\n" );
document.write( "10 south to (0,-10)<BR>\n" );
document.write( "2 west to (-2,-10)<BR>\n" );
document.write( "5 east to (3,-10)<BR>\n" );
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document.write( "distance from (0,0) to (3,-10) = sqrt[3^2 + 10^2] = sqrt(109) = 10.44 km<BR>\n" );
document.write( "Angle: tan^-1(-10/3) = -73.3 degrees = 286.7 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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