document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=825255>Question 825255</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve for x y z by elimination method\r<BR>\n" );
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document.write( "2x-3y+4z=6<BR>\n" );
document.write( "5x+y+3z=14<BR>\n" );
document.write( "3x+2y-z=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #497167 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=497167\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Choose any variable you want.  ..... I had a description here, but decided to delete it...\r<BR>\n" );
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document.write( "I would start with the y or the z variable in your example.  Choosing z:\r<BR>\n" );
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document.write( "Multiply the 3x+2y-z=0 by 4, and add it to the first equation.<BR>\n" );
document.write( "Multiply this same equation by 3, and add it to the second equation.<BR>\n" );
document.write( "You have now eliminated z, and you should have a system in x and y, without any z.\r<BR>\n" );
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document.write( "Now, decide how to multiply which equation so you can add or subtract it from the other equation and eliminate either the x or the y.  You could then simply solve for the apparant variable.  Now, find the other two variables through back-substitution for the variable you finally found. </SPAN>\n" );
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