document.write( "Question 825149: divide 105 into two parts such that one half of the first exceeds one fifth of the second by 35. find the number.\r
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document.write( "please help me to solve this. \n" );
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Algebra.Com's Answer #497134 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! x+y=105, \n" ); document.write( "x/2=y/5+35 \n" ); document.write( "x = 80, y = 25 \n" ); document.write( " |