document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69754>Question 69754</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How could I find the exact value of cos(sin^-1(3/5)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49710 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How could I find the exact value of cos(sin^-1(3/5)?\r<BR>\n" );
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document.write( "sin^-1(3/5) is an angle in the 1st quadrant because sin^-1 has a range of <BR>\n" );
document.write( "-90 to 90.<BR>\n" );
document.write( "x, y, and r are all positive in the 1st quadrant.<BR>\n" );
document.write( "You are given opp/hyp = 3/5; you need to find adjacent.<BR>\n" );
document.write( "adj=sqrt(hyp-opp) = sqrt(5^2 - 3^2) = sqrt(16) = 4<BR>\n" );
document.write( "Therefore cos(sin^-1(3/5))= 4/5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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