document.write( "Question 825006: for what values of c does |2x+1|= x+c have two solutions?
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Algebra.Com's Answer #496964 by josgarithmetic(39623)\"\" \"About 
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2x+1>0:
\n" ); document.write( "2x+1=x+c
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\n" ); document.write( "2x+1<0:
\n" ); document.write( "-2x-1=x+c\r
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\n" ); document.write( "\n" ); document.write( "Use the two resulting equations.
\n" ); document.write( "2x+1-x=c and -2x-1-x=c
\n" ); document.write( "x+1=c and -3x-1=c
\n" ); document.write( "Giving \"x%2B1=-3x-1\"
\n" ); document.write( "\"4x=-2\"
\n" ); document.write( "\"x=-1%2F2\"
\n" ); document.write( "That means: \"c=1-1%2F2=1%2F2\" and \"c=3%281%2F2%29-1=3%2F2-2%2F2=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "The equation would have just one value for c.
\n" ); document.write( "\"c=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "What if you would try solving for c first instead of x?
\n" ); document.write( "x+1=c and -3x-1=c
\n" ); document.write( "x=c-1 and -3x=c+1
\n" ); document.write( "x=c-1 and x=(c+1)/(-3)
\n" ); document.write( "then
\n" ); document.write( "c-1=-(c+1)/3
\n" ); document.write( "3c-3=-c-1
\n" ); document.write( "4c=-1+3
\n" ); document.write( "4c=2
\n" ); document.write( "\"c=1%2F2\", just like before.
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