document.write( "Question 825000: Sean's age is 5 years more than twice Doug's age. The sum of their ages is 29. Find each of their ages. \n" ); document.write( "
Algebra.Com's Answer #496939 by y6n3o9p4(20)\"\" \"About 
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Let S = Sean's age, and D = Doug's age.\r
\n" ); document.write( "\n" ); document.write( "Write it out as these equations:\r
\n" ); document.write( "\n" ); document.write( "\"S+=+2D%2B5\"
\n" ); document.write( "\"S%2BD+=+29\"\r
\n" ); document.write( "\n" ); document.write( "Use the system of elimination to subtract the second equation from the first one and isolate Doug's age.\r
\n" ); document.write( "\n" ); document.write( "\"-D+=+2D-24\"
\n" ); document.write( "\"D+=+-2D%2B24\"
\n" ); document.write( "\"3D+=+24\"
\n" ); document.write( "\"D+=+8\"\r
\n" ); document.write( "\n" ); document.write( "Plug Doug's age into one of the equations.\r
\n" ); document.write( "\n" ); document.write( "\"S%2B8+=+29\"
\n" ); document.write( "\"S+=+21\"\r
\n" ); document.write( "\n" ); document.write( "Sean's age is 21, and Doug's age is 8.
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