document.write( "Question 825009: The sum of two numbers is 51. If twice the smaller number is subtracted from the larger number, the result is 18. Find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #496935 by y6n3o9p4(20)\"\" \"About 
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Let x = the smaller number, and y = the larger number.\r
\n" ); document.write( "\n" ); document.write( "Here is the problem written as a pair of equations:\r
\n" ); document.write( "\n" ); document.write( "\"x%2By+=+51\"
\n" ); document.write( "\"y-2x+=+18\"\r
\n" ); document.write( "\n" ); document.write( "One method that can be used to solve this is the system of elimination. Subtract the second equation from the first one to isolate the x variable.\r
\n" ); document.write( "\n" ); document.write( "\"3x+=+33\"
\n" ); document.write( "Simplify: \"x+=+11\"\r
\n" ); document.write( "\n" ); document.write( "Now, plug the number into one of the two equations.\r
\n" ); document.write( "\n" ); document.write( "\"11%2By+=+51\"
\n" ); document.write( "Subtract 11 from both sides to isolate the y variable: \"y+=+40\"\r
\n" ); document.write( "\n" ); document.write( "You can check your answer by plugging the numbers into the other equation. \"40-22+=+18\"\r
\n" ); document.write( "\n" ); document.write( "The smaller number is 11, and the larger number is 40.
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