document.write( "Question 825010: Two pipes p1 & p2 can fill a tank in 40 minutes and 60 minutes respectively.Both the taps are opened and after 10 minutes p1 was shut. In how much more time would the tank be full?
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document.write( "A)30 minutes B)35 minutes \n" );
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Algebra.Com's Answer #496934 by josgarithmetic(39630) ![]() You can put this solution on YOUR website! Both pipes were used for 10 hours, and only pipe 2 was used for some unknown amount of time afterward. The amount of tank filled was 1. Let x = time in hours after the first 10 minutess.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First period: p1 and p2 together for 10 minutes. \n" ); document.write( "Second period: p2 for x minutes. \n" ); document.write( "Total Time: 1 tank.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the rate information as tanks per time. \n" ); document.write( "p1 rate is 1/40 tanks per minute. \n" ); document.write( "p2 rate is 1/60 tanks per minute \n" ); document.write( "p1 and p2 together rate is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You have from the key uniform rate idea, R*t=j meaning rate time time equals the amount of job. Specific to our example, \n" ); document.write( "SOLVE FOR x. \n" ); document.write( " |