document.write( "Question 825010: Two pipes p1 & p2 can fill a tank in 40 minutes and 60 minutes respectively.Both the taps are opened and after 10 minutes p1 was shut. In how much more time would the tank be full?
\n" ); document.write( "A)30 minutes B)35 minutes
\n" ); document.write( "

Algebra.Com's Answer #496934 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
Both pipes were used for 10 hours, and only pipe 2 was used for some unknown amount of time afterward. The amount of tank filled was 1. Let x = time in hours after the first 10 minutess.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "First period: p1 and p2 together for 10 minutes.
\n" ); document.write( "Second period: p2 for x minutes.
\n" ); document.write( "Total Time: 1 tank.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use the rate information as tanks per time.
\n" ); document.write( "p1 rate is 1/40 tanks per minute.
\n" ); document.write( "p2 rate is 1/60 tanks per minute
\n" ); document.write( "p1 and p2 together rate is \"1%2F40%2B1%2F60=%283%2B2%29%2F120=5%2F120=highlight_green%281%2F24%29\" tanks per minute.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You have from the key uniform rate idea, R*t=j meaning rate time time equals the amount of job. Specific to our example, \"highlight%28%281%2F24%2910%2B%281%2F60%29x=1%29\".
\n" ); document.write( "SOLVE FOR x.
\n" ); document.write( "
\n" );