document.write( "Question 825011: Pipe A can fill a tank in 12 hours and pipe B can empty the tank in 18 hours.Both pipes are opened at 6 am & after some time pipe B is closed,&the tank is full at 8 pm on the same day.At what time was the pipe B closed?
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document.write( "A)8 am
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document.write( "B)9 am \n" );
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Algebra.Com's Answer #496932 by josgarithmetic(39628) ![]() You can put this solution on YOUR website! The time between 6am and 8pm is made of two time periods, x and y. One combination of pipes was used for x amount of time, and another combination of pipes was used for y amount of time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sum of the time periods was 14 hours. That is the amount of time from 6am to 8pm. We have our very important first equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The filling rate when both pipes A and B are open is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When both tanks were open for x hours, the amount of tank filled was (1/36)x. \n" ); document.write( "When only tank A was open for y hours, the amount of tank DURING y was (1/12)y. \n" ); document.write( "The whole tank filled was the SUM of these amounts of the filling job: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The equations highlight-enclosed in red are your system to solve. You might want to simplify the job sum equation first, multiplying left and right by 36: \n" ); document.write( " \n" ); document.write( "' \n" ); document.write( "So now you can use the simpler system to solve for x and y: \n" ); document.write( "--------------------- \n" ); document.write( " \n" ); document.write( "--------------------- \n" ); document.write( " \n" ); document.write( "--------------------- \n" ); document.write( " |