document.write( "Question 824982: The length of a rectangle is 3 times it's width. Is both dimensions are increased by 2 centimeters, the area is 32 square centimeters. What was the original length? \n" ); document.write( "
Algebra.Com's Answer #496909 by jim_thompson5910(35256)\"\" \"About 
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The length of a rectangle is 3 times it's width. If both dimensions are increased by 2 centimeters, the area is 32 square centimeters. What was the original length?\r
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\n" ); document.write( "\n" ); document.write( "Width = x
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\n" ); document.write( "\n" ); document.write( "\"If both dimensions are increased by 2 centimeters, the area is 32 square centimeters\" ---> \"%28x%2B2%29%283x%2B2%29=32\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%283x%2B2%29=32\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%283x%2B2%29%2B2%283x%2B2%29=32\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2B2x%2B6x%2B4=32\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2B2x%2B6x%2B4-32=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2B8x-28=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%283x%2B14%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-2=0\" or \"3x%2B14=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" or \"3x=-14\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" or \"x=-14%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Toss the negative solution. So the only solution is \"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "Width = x = 2\r
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\n" ); document.write( "\n" ); document.write( "Length = 3x = 3*2 = 6\r
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\n" ); document.write( "\n" ); document.write( "The width is 2 centimeters and the length is 6 centimeters
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