document.write( "Question 769513: The one-to-one function is defined by
\n" ); document.write( "f(x)=6x/(7x-2)
\n" ); document.write( " .
\n" ); document.write( "Find f^-1 , the inverse of f . Then, give the domain and range of f^-1 using interval notation.
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Algebra.Com's Answer #496861 by tommyt3rd(5050)\"\" \"About 
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y=6x/(7x-2)
\n" ); document.write( "y(7x-2)=6x
\n" ); document.write( "7xy-2y=6x
\n" ); document.write( "7xy-6x=2y
\n" ); document.write( "x(7y-6)=2y
\n" ); document.write( "x=2y/(7y-6)\r
\n" ); document.write( "\n" ); document.write( "Inv(f(x))=2x/(7x-6)\r
\n" ); document.write( "\n" ); document.write( "dom(Inv(f(x))=(-oo,6/7)U(6/7,oo)
\n" ); document.write( "ran(Inv(f(x))=(-oo,oo)
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