document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=824890>Question 824890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let f(x) = 2x + 3. Find values for a and b such that the equation f(ax + b) = x is true for all values of x.\r<BR>\n" );
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document.write( "I've found f(ax + b) and tried to rearrange for b and solve for a by substitution but that doesn't work. I was given a hint that if two polynomials in the variable x are equal for all values of x, then the corresponding coefficients are equal.\r<BR>\n" );
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document.write( "Please help me solve this, thank you in advance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #496859 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=496859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(ax+b) = 2 * (ax+b) + 3 = 2ax+2b+3, now<BR>\n" );
document.write( "if a = 1/2 and b = -3/2 then<BR>\n" );
document.write( "2*(1/2)*x +2*(-3/2)+3 = x  for all values of x<BR>\n" );
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