document.write( "Question 824810: The line h contains the points (6,-2) and (-4,10). The equation of the line k is ax+6y+12=0 and k is perpendicular to h. Find the value of the real number a. Please help.. \n" ); document.write( "
Algebra.Com's Answer #496811 by josgarithmetic(39617)\"\" \"About 
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The line h has the slope \"%2810-%28-2%29%29%2F%28-4-6%29=12%2F%28-10%29=-6%2F5\".\r
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\n" ); document.write( "\n" ); document.write( "The line, k, is also 6y=-ax-12,
\n" ); document.write( "\"y=-%28a%2F6%29x-2\"---------line k.\r
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\n" ); document.write( "\n" ); document.write( "Line h perpendicular to line k means that \"highlight_green%28%28-6%2F5%29%2A%28-a%2F6%29=-1%29\".
\n" ); document.write( "The typically stated rule for this is, if two perpendicular lines in a plane have slopes \"m%5B1%5D\" and \"m%5B2%5D\", then \"m%5B1%5Dm%5B2%5D=-1\".
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