document.write( "Question 824833: An auto tourist made a trip of 275 miles in 8 hours. Before noon he averaged 40 mph, and after noon he averaged 25 mph. At what time did he begin his trip and when did he end it? \n" ); document.write( "

Algebra.Com's Answer #496797 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+d+\"$ = the distance he traveled in miles before noon
\n" ); document.write( " $\"+275+-+d+\"$ = the distance he traveled in miles after noon
\n" ); document.write( "------------
\n" ); document.write( "Let $\"+t+\"$ = the time in hours he traveled before noon
\n" ); document.write( " $\"+8+-+t+\"$ = the time in hours he traveled after noon
\n" ); document.write( "---------------------------------------------
\n" ); document.write( "Equation before noon:
\n" ); document.write( "(1) $\"+d+=+40t+\"$
\n" ); document.write( "Equation after noon:
\n" ); document.write( "(2) $\"+275+-+d+=+25%2A%28+8+-+t+%29+\"$
\n" ); document.write( "--------------------------
\n" ); document.write( "By substitution:
\n" ); document.write( "(2) $\"+275+-+40t+=+200+-+25t+\"$
\n" ); document.write( "(2) $\"+15t+=+75+\"$
\n" ); document.write( "(2) $\"+t+=+5+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+8+-+5+=+3+\"$
\n" ); document.write( "His trip started at 12:00 minus 5 hrs = 3:00 AM
\n" ); document.write( "It ended at 12:00 plus 3 hrs = 3:00 pm\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );