document.write( "Question 824725: An enclosed ski lift can hold a mx of 1200 pounds. Six people want to ride the ski lift together. Libby has some measurements from the data of how much each person weighed, including their equipment. Which measure would be the most useful to determine if the people can safely use the ski lift together?
\n" ); document.write( "mean
\n" ); document.write( "median
\n" ); document.write( "mode
\n" ); document.write( "range
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Algebra.Com's Answer #496769 by KMST(5328)\"\" \"About 
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The \"highlight%28mean%29\" would be the most useful of the listed measurements,
\n" ); document.write( "because \"6%2Amean=sum\"\"of\"\"weights\" .
\n" ); document.write( "If the mean is \"mean%3C=200pounds\" ,
\n" ); document.write( "then \"total\"\"weight=6%2Amean%3C=6%2A200pounds=1200pounds\" ,
\n" ); document.write( "and the 6 people can ride together.
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\n" ); document.write( "If we knew that the median and mode were both \"200pounds\" we would still not know if the 6 people could ride together.
\n" ); document.write( "Maybe 4 of them weigh \"200pounds\" with their equipment, a fifth person is lighter and the sixth person is heavier.
\n" ); document.write( "That would make \"median=mode=200pounds\" , but it would all depend on the weights of the fifth and sixth people.
\n" ); document.write( "If their weights (including equipment) add up to \"400pounds\" or less the total weight would be
\n" ); document.write( "\"total%3C=4%2A200pounds%2B400pounds=1200pounds\" and they can ride together.
\n" ); document.write( "The range would not help either, unless we knew the range did not include \"200pounds\" .
\n" ); document.write( "If the range was fully below \"200pounds\" we would know each person weighs less than \"200pounds\" including equipment,
\n" ); document.write( "and the total would be less than \"6%2A200pounds=1200pounds\" .
\n" ); document.write( "If the range was fully above \"200pounds\" we would know each person weighs more than \"200pounds\" including equipment,
\n" ); document.write( "and the total would be more than \"6%2A200pounds=1200pounds\" .
\n" ); document.write( "If the range includes \"200pounds\" , we have no clue.
\n" ); document.write( "With a \"160pounds\" to \"210pounds\" range,
\n" ); document.write( "we could have five \"210pound\" people and one \"160pound\" person for a total weight of
\n" ); document.write( "\"5%2A210pounds%2B160pounds=1050pounds%2B160pounds=1210pounds\" , or
\n" ); document.write( "we could have five \"160pound\" people and one \"210pound\" person for a total weight of
\n" ); document.write( "\"5%2A160pounds%2B210pounds=800pounds%2B210pounds=1010pounds\" .
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