document.write( "Question 824721: A parabola cuts the x-axis at 1 and 3 and the y-axis at 6. Make up the equation of the parabola and sketch the parabola showing clearly the turning point. \n" ); document.write( "
Algebra.Com's Answer #496741 by ankor@dixie-net.com(22740)\"\" \"About 
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A parabola cuts the x-axis at 1 and 3 and the y-axis at 6.
\n" ); document.write( " Make up the equation of the parabola and sketch the parabola showing clearly the turning point.
\n" ); document.write( ":
\n" ); document.write( "From the x intercepts we have two factors
\n" ); document.write( "(x-1)(x-3) Foils to x^2 - 3x - x + 3
\n" ); document.write( "multiply equation by 2 to get a y intercept of 6
\n" ); document.write( "y = 2x^2 - 8x + 6, is the equation
\n" ); document.write( "looks like this
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-4%2C+5%2C+-10%2C+10%2C+2x%5E2-8x%2B6%29+\"
\n" ); document.write( "you can see the turning point at the axis of symmetry is x=2
\n" ); document.write( "find y
\n" ); document.write( "y = 2(2^2) - 8(2) + 6
\n" ); document.write( "y = 8 - 16 + 6
\n" ); document.write( "y = -2 \n" ); document.write( "
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