document.write( "Question 824712: A man walking on beach recognized his log lost friend 50 meters away they started running towards each other at the same time. If the man's rate is 1.5 meters per second while that of his friend is 1 meter per second how far did each other run when thy meet? \n" ); document.write( "
Algebra.Com's Answer #496739 by ankor@dixie-net.com(22740)\"\" \"About 
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A man walking on beach recognized his long lost friend 50 meters away
\n" ); document.write( "they started running towards each other at the same time.
\n" ); document.write( "If the man's rate is 1.5 meters per second while that of his friend is 1 meter per second how far did each other run when thy meet?
\n" ); document.write( ":
\n" ); document.write( "Let t = time in seconds for them to meet
\n" ); document.write( ":
\n" ); document.write( "Write a dist equation; dist = speed * time
\n" ); document.write( "When they meet they will have traveled a total of 50 m
\n" ); document.write( "1.5t + 1t = 50
\n" ); document.write( "2.5t = 50
\n" ); document.write( "t = 50/2.5
\n" ); document.write( "t = 20 seconds
\n" ); document.write( "then
\n" ); document.write( "1.5 * 20 = 30 meters traveled by the first man
\n" ); document.write( "and
\n" ); document.write( "1 * 20 = 20 meters traveled by the friend \n" ); document.write( "
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