document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=824629>Question 824629</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve this problem by using a two order system.\r<BR>\n" );
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document.write( "A man invests $5,200, part at 4% and the balance at 3%. If his total income for the two investments is $194, how much money did he invest at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #496691 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=496691\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man invests $5,200, part at 4% and the balance at 3%. If his total income for the two investments is $194, how much money did he invest at each rate?<BR>\n" );
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document.write( "Let x = amount ($) invested at 4%<BR>\n" );
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document.write( "5200-x = amount ($) invested at 3%<BR>\n" );
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document.write( ".04x + .03(5200-x) = 194<BR>\n" );
document.write( ".04x + 156-.03x = 194<BR>\n" );
document.write( ".01x + 156 = 194<BR>\n" );
document.write( ".01x = 38<BR>\n" );
document.write( "x = $3800 (amount invested at 4%)<BR>\n" );
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document.write( "amount invested at 3%:<BR>\n" );
document.write( "5200-3800 = $1400 </SPAN>\n" );
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