document.write( "Question 824672: for the given function find the following function value( im not sure if this is how you write it the way it shows is f(x)-3 square root over x-1
\n" ); document.write( "f(x)=3/x-1
\n" ); document.write( "find f (-63)
\n" ); document.write( "find f (28)
\n" ); document.write( "find f (126)
\n" ); document.write( "find f (-26)\r
\n" ); document.write( "\n" ); document.write( "I am soooo lost can anyone help me out
\n" ); document.write( "

Algebra.Com's Answer #496673 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Did you mean \"f%28x%29=3%2F%28x-1%29\" or \"f%28x%29=3%2Fx-1\" ?
\n" ); document.write( "They are not the same. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Whichever is the function you want, \"find the function value\" means replace x in the function expression with the specified value, and COMPUTE what this value is. Simple substitution and then computation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "What if you wanted, f(21)?
\n" ); document.write( "Is your function, \"3%2F%28x-1%29\"?
\n" ); document.write( "'
\n" ); document.write( "\"3%2F%2821-1%29\"
\n" ); document.write( "\"3%2F20\", and that's it.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Taking another look at your description, did you mean, \"f%28x%29=3%2Asqrt%281%2F%28x-1%29%29\"?
\n" ); document.write( "
\n" );