document.write( "Question 824441: find the area of a right triangle whose leg measures 6 feet and whose hypotenuse measures 10 feet \n" ); document.write( "
Algebra.Com's Answer #496497 by TimothyLamb(4379)\"\" \"About 
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\n" ); document.write( "hyp = sqrt( aa + bb )
\n" ); document.write( "10 = sqrt( aa + 6*6 )
\n" ); document.write( "100 = aa + 36
\n" ); document.write( "aa = 100 - 36
\n" ); document.write( "a = sqrt( 100 - 36 )
\n" ); document.write( "a = sqrt( 64 )
\n" ); document.write( "a = 8
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\n" ); document.write( "answer:
\n" ); document.write( "area = (1/2)*8*6
\n" ); document.write( "area = 24 sq.ft
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