document.write( "Question 824278: alice, who is 1.2m tall, is standing of 12m from a building as shown. From her point of view, the angel of view for the top and bottom of the building is 41 degrees. how tall is the building to the nearest tenth of a metre? \n" ); document.write( "
Algebra.Com's Answer #496482 by TimothyLamb(4379)\"\" \"About 
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\n" ); document.write( "use similar right triangles:
\n" ); document.write( "from top of Alice's head to the building, and
\n" ); document.write( "from base of building to Alice's feet along the ground
\n" ); document.write( "---
\n" ); document.write( "tanA = opp/adj
\n" ); document.write( "tanA = 1.2/12
\n" ); document.write( "A = arctan( 1.2/12 )
\n" ); document.write( "A = 5.710593137499643 degrees
\n" ); document.write( "---
\n" ); document.write( "use right triangle from top of Alice's head to the building, then up to the top of the building:
\n" ); document.write( "---
\n" ); document.write( "B = 41 - 5.710593137499643
\n" ); document.write( "B = 35.289406862500357 degrees
\n" ); document.write( "---
\n" ); document.write( "tanB = opp/adj
\n" ); document.write( "tanB = opp/12
\n" ); document.write( "opp = 12*tanB
\n" ); document.write( "opp = 12*tan(35.289406862500357)
\n" ); document.write( "opp = 8.493143180846317 m
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "building height = opp + 1.2
\n" ); document.write( "building height = 8.493143180846317 + 1.2
\n" ); document.write( "building height = 9.693143180846317
\n" ); document.write( "building height = 9.7 m
\n" ); document.write( "---
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