document.write( "Question 824418: Solve the problem.\r
\n" ); document.write( "\n" ); document.write( "The manufacturer of a CD player has found that the revenue R (in dollars) is
\n" ); document.write( "R(p)=-5p(squared)+1330p when the unit price is p dollars. If the manufacturer sets the price p to maximize revenue, what is the maximum revenue to the nearest whole dollar?
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Algebra.Com's Answer #496453 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"R%28p%29=-5p%5E2%2B1330p\"
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\n" ); document.write( "\"-5p%5E2%2B1330p=0\" will have a maximum.
\n" ); document.write( "For this maximum,
\n" ); document.write( "\"p=%28-1330%2B-+sqrt%281330%5E2-4%2A%28-5%29%2A0%29%29%2F%282%2A%28-5%29%29\"
\n" ); document.write( "\"p=%28-1330%2B-+sqrt%281330%29%29%2F%28-10%29\"
\n" ); document.write( "\"p=133%2B-+%281%2F10%29sqrt%281330%29\"
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\n" ); document.write( "Looking at the middle of the two possible p values,
\n" ); document.write( "\"p=133%2F2\" is where the maximum revenue should be.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28R%28133%2F2%29=-5%2A%28133%2F2%29%5E2%2B1330%28133%2F2%29%29\", maximum revenue.
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