document.write( "Question 824392: I need detail solution:
\n" ); document.write( "A = ( \"sqrt%282%29\" + \"sqrt%283%29\" + \"sqrt%285%29\")( \"sqrt%282%29\"\"sqrt%283%29\" + \"sqrt%285%29\") and B = ( \"sqrt%282%29\" + \"sqrt%283%29\"\"sqrt%285%29\")(−\"sqrt+%282%29\" + \"sqrt%283%29\" + \"sqrt%285%29\") find C=AB\r
\n" ); document.write( "\n" ); document.write( "(In the \"A\" I've got 4-2\"sqrt%2815%29\", but I can't solve B)
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Algebra.Com's Answer #496434 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
A) let u = square root (2) + square root (5)
\n" ); document.write( " then we can rewrite problem as
\n" ); document.write( " (u + square root(3)) * (u - square root(3))
\n" ); document.write( " u^2 - 3
\n" ); document.write( " (2 + 2*square root(2)*square root(5) +5) - 3
\n" ); document.write( " (2 +2*square root(10) +5 -3)
\n" ); document.write( " (4 +2*square root(10))
\n" ); document.write( " 2*(2 + square root(10))
\n" ); document.write( "B) let v = square root(2) - square root (5)
\n" ); document.write( " then we can rewrite problem as
\n" ); document.write( " (square root(3) + v) * (square root(3) - v)
\n" ); document.write( " 3 - v^2
\n" ); document.write( " 3 - (2 -2*square root(2)*square root(5)+5)
\n" ); document.write( " 3 - (2 -2*square root(10)+5)
\n" ); document.write( " 3 - 2 +2*square root(10) - 5
\n" ); document.write( " 2*square root(10) - 4
\n" ); document.write( " 2*(square root(10) - 2)
\n" ); document.write( "now we are asked what is C = AB
\n" ); document.write( "C = (2*square root(10) + 4) * (2*square root(10) -4)
\n" ); document.write( "C = 4*10 - 16
\n" ); document.write( "C = 40 -16
\n" ); document.write( "C = 24\r
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