document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=824397>Question 824397</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need detail solution (and explanation what formulas should be used): <BR>\n" );
document.write( " A Nintendo DS costs one hundred and twenty British pounds sterling 12000 pennies . I decide today, 17th<BR>\n" );
document.write( " April 2013, to put 10 pennies aside. Tomorrow I’ll put 15 pennies, the day after 20 pennies, the day after that 25p and<BR>\n" );
document.write( " so on, increasing the amount by 5 pennies every day. At which date will I have enough to buy the<BR>\n" );
document.write( " Nintendo? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #496429 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=496429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10+15+20+25 ...<BR>\n" );
document.write( "a_n = 5 (n+1) (for all terms given)<BR>\n" );
document.write( "12000 = 5 (n+1) (for all terms given)<BR>\n" );
document.write( "n = 2399 days<BR>\n" );
document.write( "Wednesday, April 17, 2013+2399 days<BR>\n" );
document.write( "Monday, November 11, 2019<BR>\n" );
document.write( "which is the 101 st anniversary of the end of WWI<BR>\n" );
document.write( "2147 days from now xmas </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );