document.write( "Question 824374: 2 taps (one large and one small) fill a tank together in total of 48 minutes.
\n" ); document.write( "difference between time taken to fill the tank by small tap (only) and large tap(only) but (separately) is 40 minutes.
\n" ); document.write( "find the time taken by each tap separately
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #496401 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let large tap fill in x minutes
\n" ); document.write( "small tap will fill in (x-40) minutes\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "They together fill in 48 minutes
\n" ); document.write( "1/48 of the job is done by both iin 1 minute\r
\n" ); document.write( "\n" ); document.write( "large tap does 1/x of the job in 1 minute
\n" ); document.write( "small tap does 1/(x-40) of the job in 1 minute\r
\n" ); document.write( "\n" ); document.write( "1/x + 1/(x-40) = 1/48\r
\n" ); document.write( "\n" ); document.write( "LCM\r
\n" ); document.write( "\n" ); document.write( "(x-40+x)/x(x-40) = 1/48\r
\n" ); document.write( "\n" ); document.write( "(2x-40)=(x^2-40x)/48\r
\n" ); document.write( "\n" ); document.write( "48(2x-40)= x^2-40x\r
\n" ); document.write( "\n" ); document.write( "96x-1920=x^2-40x\r
\n" ); document.write( "\n" ); document.write( "x^2-136x+1920=0\r
\n" ); document.write( "\n" ); document.write( "x^2-120x-16x+1920=0\r
\n" ); document.write( "\n" ); document.write( "x(x-120)-16(x-120)=0\r
\n" ); document.write( "\n" ); document.write( "(x-16)(x-120)=0\r
\n" ); document.write( "\n" ); document.write( "x=16 OR 120 minutes\r
\n" ); document.write( "\n" ); document.write( "large tap cannot take 16 minutes as difference is 40\r
\n" ); document.write( "\n" ); document.write( "large tap 120 minutes
\n" ); document.write( "small tap = 80 minutes\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );