document.write( "Question 824109: John had $30,000to invest. He invest part of this money in bonds paying 12% annual simple interest and the rest of the money in saving account giving 4% annual interest. at the end of the year he received $2,400 as extra income. how much money did John place in each investment. show your work \r
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Algebra.Com's Answer #496400 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 12.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 4.00% per annum ------------ Amount invested = y \n" ); document.write( " 30000 \n" ); document.write( "Interest----- 2400.00 \n" ); document.write( " \n" ); document.write( "Part I 12.00% per annum ---x \n" ); document.write( "Part II 4.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 30000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "12.00% x + 4.00% y= 2400 \n" ); document.write( "Multiply by 100 \n" ); document.write( "12 x + 4 y= 240000.00 --------2 \n" ); document.write( "Multiply (1) by -12 \n" ); document.write( "we get \n" ); document.write( "-12 x -12 y= -360000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -8 y= -120000 \n" ); document.write( "divide by -8 \n" ); document.write( " y = 15000 \n" ); document.write( "Part I 12.00% $ 15000 \n" ); document.write( "Part II 4.00% $ 15000 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "15000 --------- 12.00% ------- 1800.00 \n" ); document.write( "15000 ------------- 4.00% ------- 600.00 \n" ); document.write( "Total -------------------- 2400.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |