document.write( "Question 824357: If 5 is added both to the numerator and denominator of a fraction, the result is equivalent to 3/4. If 3 is subtracted from both numerator and denominator of the original fraction, the new result is equivalent to 1/4. Find the orginal fraction. \n" ); document.write( "
Algebra.Com's Answer #496368 by josmiceli(19441) You can put this solution on YOUR website! Let the original fraction = \n" ); document.write( "given: \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "---------------------------- \n" ); document.write( "Multiply both sides of (1) by \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "------------------ \n" ); document.write( "Multiply both sides of (2) by \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "Add (1) and (2) \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and, since \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "------------ \n" ); document.write( " \n" ); document.write( "The original fraction is 4/7 \n" ); document.write( "check: \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK \n" ); document.write( " \n" ); document.write( " |