document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=824351>Question 824351</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If each side of a square is increased by 3cm , its area is increased by 45cm^2. Find the length of a side of the original square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #496352 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=496352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+3)^2 = x^2 + 45\r<BR>\n" );
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document.write( "x^2 + 6x + 9 = x^2 + 45\r<BR>\n" );
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document.write( "x^2 + 6x + 9 - x^2 = 45\r<BR>\n" );
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document.write( "6x + 9 = 45\r<BR>\n" );
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document.write( "6x = 45 - 9\r<BR>\n" );
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document.write( "6x = 36\r<BR>\n" );
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document.write( "x = 36/6\r<BR>\n" );
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document.write( "x = 6\r<BR>\n" );
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document.write( "The side length of the original square is <font color=\"red\">6 cm</font> </SPAN>\n" );
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